Copyright ©2003 by Paul Niquette. All rights reserved. |
1. Pick the number of times
a week that you would like to have dinner out. |
Let p be the number you pick.
Notice, if you have only one "dinner" per day, p < 8. |
2. Multiply this number by 2. | 2p |
3. Add 5. | 2p + 5 |
4. Multiply by 50. | 50(2p + 5) = 100p + 250 |
5. If you have already had your
birthday this year, add 1753. |
100p + either...
250 + 1753 = 2003 or... 250 + 1752 = 2002 |
6. Now subtract the four digit
year in which you were born. |
100p + either...
2003 - y or 2002 - y |
ophisticated solvers of this puzzle as well as psychics know that the difference between the year of your most recent birthday and that in which you were born is your age. Of course, using the procedure in the statement of this puzzle, you did come out younger than you really are -- unless you happened to notice that the puzzle was published in 2003. To make the puzzle work for your e-mail recipients in the future, you will need to change the addends in Step 5 to 250 and 251 years ago. Then, too, your recipients better not be more than five-score years old, for we see only two digits of age allowed by the prescribed Psychic Math set forth above. How might you change the procedure to accommodate centenarians who enjoy solving puzzles?There doubtless exists a conventional name for this huge class of prestiation, in which...
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